Another math problem im stuck on.
the price of a dress is reduced by 40%. when the dress still doesnt not sell, it is reduced by 40% again.
The reduced price after both reduction is $72.
What was the original price?
Hello, urlostaznbro!
The price of a dress is reduced by 40%.
When the dress still doesnt not sell, it is reduced by 40% again.
The reduced price after both reduction is $72.
What was the original price?
Let's baby-talk our way through it . . .
Let $\displaystyle x$ = original price of the dress.
It is reduced by 40%, so the sale price is 60% of $\displaystyle x:\;\;0.60x$
The dress doesn't sell, so it is reduced by another 40%.
The final price is $\displaystyle 60\%$ of $\displaystyle 0.60x:\;\;(0.60)(0.60x) \:=\:0.36x$
. . which is equal to $\displaystyle \$72$.
And there is our equation: .$\displaystyle 0.36x\:=\:72 \quad\Rightarrow\quad x \:=\:200$
Therefore, the original price was $\displaystyle \$200$.
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Check
$\displaystyle \begin{array}{ccccc}\text{Original price:} & \$200 \\
\text{less 40}\%: & -80\\
\text{Sale price:} & \$120\\
\text{less 40}\%: & -48\\
\text{Final price:} & \$72\end{array}$