Another math problem im stuck on.

the price of a dress is reduced by 40%. when the dress still doesnt not sell, it is reduced by 40% again.

The reduced price after both reduction is $72.

What was the original price?

Printable View

- Jan 14th 2007, 02:17 PMu.........help plese ;[
Another math problem im stuck on.

the price of a dress is reduced by 40%. when the dress still doesnt not sell, it is reduced by 40% again.

The reduced price after both reduction is $72.

What was the original price? - Jan 14th 2007, 02:43 PMSoroban
Hello, urlostaznbro!

Quote:

The price of a dress is reduced by 40%.

When the dress still doesnt not sell, it is reduced by 40% again.

The reduced price after both reduction is $72.

What was the original price?

Let's baby-talk our way through it . . .

Let $\displaystyle x$ = original price of the dress.

It is reduced by 40%, so the sale price is 60% of $\displaystyle x:\;\;0.60x$

The dress doesn't sell, so it is reduced by another 40%.

The final price is $\displaystyle 60\%$ of $\displaystyle 0.60x:\;\;(0.60)(0.60x) \:=\:0.36x$

. . which is equal to $\displaystyle \$72$.

And*there*is our equation: .$\displaystyle 0.36x\:=\:72 \quad\Rightarrow\quad x \:=\:200$

Therefore, the original price was $\displaystyle \$200$.

~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~

Check

$\displaystyle \begin{array}{ccccc}\text{Original price:} & \$200 \\

\text{less 40}\%: & -80\\

\text{Sale price:} & \$120\\

\text{less 40}\%: & -48\\

\text{Final price:} & \$72\end{array}$