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Math Help - A little bit of help needed please!

  1. #1
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    A little bit of help needed please!

    I need a little bit of help with two questions that are confusing me quite a lot.

    [1]
    find the slope and y-intercept of the following: 5x-2y=3

    [2]
    Write an equation for the line going through the points (3, 2) and (-2,4).

    Thanks for your help guys!

    Drakmord.
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  2. #2
    MHF Contributor
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    Quote Originally Posted by drakmord View Post
    I need a little bit of help with two questions that are confusing me quite a lot.

    [1]
    find the slope and y-intercept of the following: 5x-2y=3

    put it in this form : 2y=5x-3 .. y=(5/2)x-3/2

    From here , we can see that m=5/2 and y- intercept =-3/2

    [2]
    Write an equation for the line going through the points (3, 2) and (-2,4).

    Thanks for your help guys!

    Gradient=(2-4)/(3+2)=-2/5

    Then we know this line passes through (3,2) , y-2=(-2/5)(x-3)

    Then expand it . I assume u know this formula : y-y1=m(x-x1)

    Drakmord.
    .
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  3. #3
    Junior Member
    Joined
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    Quote Originally Posted by drakmord View Post
    I need a little bit of help with two questions that are confusing me quite a lot.

    [1]
    find the slope and y-intercept of the following: 5x-2y=3

    [2]
    Write an equation for the line going through the points (3, 2) and (-2,4).

    Thanks for your help guys!

    Drakmord.

    Rewrite the equation in standard form:

    y=\frac{5x-3}{2}

    Choose two arbitrary x values, solve for y, and then solve for slope using slope = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}....you can also see it because it's in standard form...but you should understand it better if you calculate it out.

    The y-intercept occurs at the point where x= 0, so just make x= 0 and solve for y.

    2)

    We can use the point-slope form of a line for this:

    y-y_{1}=m(x-x_{1})

    Input the values of one of the points into the equation, and then the other. Solve for the slope, m, and then you're set.
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  4. #4
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    Jul 2009
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    so would the working be: y_{2}-y_{1}=m(x_{1}-x_{2}) \rightarrow 4-2=m(-2-3) \rightarrow 2=m(-5)so, m=2\div5 \rightarrow m=-\frac25\therefore 2=-\frac25(-5)?

    Thank you for your help!

    Drakmord
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