1. ## A little bit of help needed please!

I need a little bit of help with two questions that are confusing me quite a lot.

[1]
find the slope and y-intercept of the following: 5x-2y=3

[2]
Write an equation for the line going through the points (3, 2) and (-2,4).

Drakmord.

2. Originally Posted by drakmord
I need a little bit of help with two questions that are confusing me quite a lot.

[1]
find the slope and y-intercept of the following: 5x-2y=3

put it in this form : 2y=5x-3 .. y=(5/2)x-3/2

From here , we can see that m=5/2 and y- intercept =-3/2

[2]
Write an equation for the line going through the points (3, 2) and (-2,4).

Then we know this line passes through (3,2) , y-2=(-2/5)(x-3)

Then expand it . I assume u know this formula : y-y1=m(x-x1)

Drakmord.
.

3. Originally Posted by drakmord
I need a little bit of help with two questions that are confusing me quite a lot.

[1]
find the slope and y-intercept of the following: 5x-2y=3

[2]
Write an equation for the line going through the points (3, 2) and (-2,4).

Drakmord.

Rewrite the equation in standard form:

$y=\frac{5x-3}{2}$

Choose two arbitrary x values, solve for y, and then solve for slope using $slope = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}$....you can also see it because it's in standard form...but you should understand it better if you calculate it out.

The y-intercept occurs at the point where x= 0, so just make x= 0 and solve for y.

2)

We can use the point-slope form of a line for this:

$y-y_{1}=m(x-x_{1})$

Input the values of one of the points into the equation, and then the other. Solve for the slope, m, and then you're set.

4. so would the working be: $y_{2}-y_{1}=m(x_{1}-x_{2}) \rightarrow 4-2=m(-2-3) \rightarrow 2=m(-5)so, m=2\div5 \rightarrow m=-\frac25\therefore$ $2=-\frac25(-5)$?