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Math Help - solve for x

  1. #1
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    solve for x

    If someone could show me the procedure to these two equations, or one would be fine I dont know what to do.

    a) (2x-1)/(x+2)=4/5

    b) (4)/(x-1)+(2)/(x+1)=(35)/(x-1)
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  2. #2
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     \frac{2x-1}{x+2}=\frac{4}{5}

     5(2x-1)=4(x+2)

     10x-5=4x+8

     6x=13

     x=\frac{13}{6}
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  3. #3
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    THANK YOU you dont know how much you helped me. My logic was messed up today, if it wasn't for that I would have had to stay up all night at least I can sleep 3 hours now. Thanks.
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  4. #4
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     \frac{4}{x-1}+\frac{2}{x+1}=\frac{35}{x^2-1}

     \frac{4(x+1)+2(x-1)}{(x-1)(x+1)}=\frac{35}{x^2-1}

    As

     (x-1)(x+1)= x^2-1 then

     4(x+1)+2(x-1)=35

    Now use the same techniques I displayed in my first post.
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