If someone could show me the procedure to these two equations, or one would be fine I dont know what to do.
a) (2x-1)/(x+2)=4/5
b) (4)/(x-1)+(2)/(x+1)=(35)/(x²-1)
$\displaystyle \frac{4}{x-1}+\frac{2}{x+1}=\frac{35}{x^2-1}$
$\displaystyle \frac{4(x+1)+2(x-1)}{(x-1)(x+1)}=\frac{35}{x^2-1}$
As
$\displaystyle (x-1)(x+1)= x^2-1$ then
$\displaystyle 4(x+1)+2(x-1)=35$
Now use the same techniques I displayed in my first post.