solve for x

**Lonn** · September 1st 2009, 08:37 PM

If someone could show me the procedure to these two equations, or one would be fine I dont know what to do.

a) (2x-1)/(x+2)=4/5

b) (4)/(x-1)+(2)/(x+1)=(35)/(x²-1)

**pickslides** · September 1st 2009, 08:44 PM

$\frac{2x-1}{x+2}=\frac{4}{5}$

$5(2x-1)=4(x+2)$

$10x-5=4x+8$

$6x=13$

$x=\frac{13}{6}$

**Lonn** · September 1st 2009, 08:52 PM

THANK YOU you dont know how much you helped me. My logic was messed up today, if it wasn't for that I would have had to stay up all night at least I can sleep 3 hours now. Thanks.

**pickslides** · September 1st 2009, 09:51 PM

$\frac{4}{x-1}+\frac{2}{x+1}=\frac{35}{x^2-1}$

$\frac{4(x+1)+2(x-1)}{(x-1)(x+1)}=\frac{35}{x^2-1}$

As

$(x-1)(x+1)= x^2-1$ then

$4(x+1)+2(x-1)=35$

Now use the same techniques I displayed in my first post.

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