1/h(x+h)^2

1/hx^2

What would you do to make the above rationals NOT be over 1?

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- Sep 1st 2009, 04:59 PMnautica17How would you undo these?
1/h(x+h)^2

1/hx^2

What would you do to make the above rationals NOT be over 1? - Sep 1st 2009, 05:22 PMskeeter
- Sep 1st 2009, 05:28 PMnautica17
There is no other question. I just want to make what I listed to not be over 1.

The original equation that I am solving is:

((1/h(x+h)^2)-(1/hx^2)) / h

I just wanted to make those two parts in the numerator a little bit more simpler so that they are not fractions. How do I go about doing so? Or is there some other way I can solve. - Sep 1st 2009, 05:48 PMskeeter
- Sep 1st 2009, 06:01 PMnautica17
Yea I did. Then I just multiplied the top and bottom by 1/h after I set up the equation and got to this point. Now I'm stuck. Sorry for lack of info on my part. I have a bunch of homework and I'm trying to multi-task everything right now.

- Sep 1st 2009, 06:04 PMStroodle
- Sep 1st 2009, 06:08 PMnautica17
- Sep 1st 2009, 06:14 PMskeeter
your difference quotient should be ...

it can be rewritten as ...

work inside to get a common denominator ...

expand the numerator ...

combine like terms in the numerator ...

factor out of the numerator ...

divide out the h's ...

if you have covered limits in class, take the limit as and simplify ... - Sep 1st 2009, 06:29 PMnautica17
Thank-you that explains it. :) I guess my tutor at school didn't know what they were doing.