I need to graph this function f(x)=x/(sqrt(1+3x)-1)
I cannot figure out how I get the starting point of the graph (from the left).
It needs to start somewhere around x= -.3 and y= .43
How do I know where the exact startpoint is, without making a table?
So, do I understand that I do not need to solve the equation
I do not really understand what you mean with the additional information you posted. Would you mind explaining it in a different way?
I am a little confused and do not know how to actually find the starting point of the graph (or the point where I have to start drawing the graph)
Yeh sorry, I confused matters because I was not familiar with the term starting point, but now I understand.
Bascially, ignore everything I said and just read this.
The denominator has a square root in it, and we know that we can only take the square root of a number that is greater than or equal to zero. Therefore the starting point will be the point x, such that what's inside the square root is greater than or equal to zero.
So, mathematically: and after rearranging, we arrive at
Sorry again, hope this cleared things up.
Oh, ok. So I only evaluate the term under the root, wich cannot be zero. Then I get my x-value which I plug in f(x) to get my y-value. Finally I have my p(x,y) where I need to start drawing the graph.
Thank you so much!
DBA, x should not be lower than -1/3, the square root term would become meaningless. See the graph . . . .