Hi guys I'm having a bit of bother

using the discrminant I've to find the values for p that mean the following can be true

px²-10+p=0

and

x²+2p+1=2(p-1)x

any help would be great, regards paul

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- Sep 1st 2009, 11:59 AM #1

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- Sep 1st 2009, 01:24 PM #2
Definition of discriminant: $\displaystyle \Delta = b^2 - 4ac$.

$\displaystyle px^2 + (p - 10) = 0$: $\displaystyle a = p, ~ b = 0, ~ c = p - 10$.

$\displaystyle x^2 - 2(p - 1) x + (2p + 1) = 0$: $\displaystyle a = 1, ~ b = -2(p-1), ~ c = 2p + 1$.

In each case, substitute the values of a, b and c into the discriminant and solve $\displaystyle \Delta \geq 0$ (assuming you mean true for REAL values of x).

If you need more help, please show the work you've done and where you get stuck.