1) Area of the circle is 3.14.
2) Thus area of the triangle is 3.14.
3) So hb/2=3.14, where h is the height of he triangle and b is the length of the base.
4) Hence hb = 6.28, but b = 3
5) Then 3h = 6.28
6) Then h = 2.09
Hi, this is my first post in the forums, so please take it easy on me. I'm currenlty in Algebra 2 and I was confused on a question.
You see, the problem is that there is a circle with a radius of 1, and a triangle with a base of 3 and an unknown height. They tell me that the area of the circle is there same as the triangle, and that the answer is 2.09.
Problem is, I have to show work, and I can only get two answers from this: 1.05 (which I got from doing 3.14 multiplied by 1squared and then dividing 3.14 by 3 getting 1.05)
or 3.29 (which I got from doing 3.14squared and then divide it by 3)
The reason I divide it by 3 is because I figure since 3 x height will equal the area, then if I divide the area by 3 I'll get the height.
Help me guys!