Okay, so this

*may* seem a bit simple for here, and I wasn't sure, but this is from my University past paper. The question reads:

*A chocolate company produce boxes of chocolates with mean $\displaystyle 1kg$. It is decided that all boxes weighing less than $\displaystyle 990g$ or more than $\displaystyle 1020g$ will be re-packed. If the weight of the boxes is Normally distributed with standard deviation $\displaystyle 20g$, what percentage of boxes will be repacked?*
So I got from this that...

$\displaystyle X\sim N(1,0.02^{2})$ and I was trying to find $\displaystyle 1-\left(P(0.99\leq X\leq 1.02)\right)$ (because the stuff in the $\displaystyle P$ would be the boxes that were the right weight, so 1 minus that would be boxes to be repacked). However, after standardising and using the tables I'm given and what not, with this I get a percentage that, to me, seems a bit high

something like 43%.

Can anyone help? Have I made a misunderstanding somewhere?