Q. If all the 1 pound cans of beans filled by a food processor have a mean weight of 16.00 ounces with a standard deviation of 0.02 ounces, at least what percentage of the cans must contain between 15.80 and 16.20 ounces of beans, assuming the weights are normally distributed?

A.

(16.20-15.80) x SQRT 16 / 0.02

= (0.4)(4)/0.02

= 1.6/0.02

= 80%

Is this correct or have i used the wrong equation?