let X be the number of passengers that show up
X follows a binomial distribution with n= 100 and p = 0.96 (q=0.04)
I'm having some trouble with this one:
An airline finds that 4 percent of the passengers that make reservations on a particular flight will not show up (not that each individual person has a 4 percent chance of showing up which is what is throwing me off). Consequently, their policy is to sell 100 reserved seats on a plane that only has 98 seats. Find the probability that ever person who shows up for the flight will find a seat available.