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Thread: Summation regarding variance

  1. July 20th 2009, 09:42 AM #1
    Pink Lady
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    Summation regarding variance

    Hi!
    How does one go about the following problem?
    (a+1)^2 + (a+2)^2 + (a+3)^2 + ... + (a+n)^2 ?
    I am really stuck, so any help will be appreciated! Thanks
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  2. July 20th 2009, 09:59 AM #2
    Plato
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    Quote Originally Posted by Pink Lady View Post
    Hi!
    How does one go about the following problem?
    (a+1)^2 + (a+2)^2 + (a+3)^2 + ... + (a+n)^2 ?
    \sum\limits_{k = 1}^n {\left( {a + k} \right)^2 } = \sum\limits_{k = 1}^n {a^2 } + 2a\sum\limits_{k = 1}^n k + \sum\limits_{k = 1}^n {k^2 }
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