Originally Posted by

**redpack** In a smoking survey among boys between the ages of 12 and 17, 78% prefer to date

nonsmokers. 1% prefer to date smokers, and 21% don’t care. Suppose seven such boys are

selected randomly and X equals the number who prefer to date nonsmokers and Y equals the

number who prefer to date smokers.

(a) Determine the joint p.m.f. of X and Y. Be sure to include the support of the p.m.f.

$\displaystyle \frac{7!}{x!y!(7-x-y)!}(0.78)^x(0.01)^y(0.21)^{7-x-y}$

(b) Find the marginal p.m.f. of X. Again, include the support.

$\displaystyle \frac{7!}{x!(7-x)!}(0.78)^x(0.22)^{7-x}$ where x=0,...,7.

Thank you!