A carton contains 12 eggs, 5 of which are cracked. If we randomly select 6 eggs for hard-boiling, what is the probability that two of the cracked eggs are selected? Or this one, i'm lost. Any help would be appreciated.
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hypergeometric since this is without replacement $\displaystyle { {5\choose 2}{7\choose 4}\over {12\choose 6}} $ is the probability of EXACTLY 2 cracked and 4 non-cracked eggs.
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