1. ## significance level

880 randomly chosen people surveyed. 493 of them admitted to chewing gum. If we use a signifagant level of 0.01, can we conclude that a majority of people chew gum?

2. test $H_0=.5" alt="H_0=.5" /> vs. $H_a>.5" alt="H_a>.5" />

$\hat p=493/880$ the test statistic is ${\hat p -.5\over \sqrt{(.5)(.5)\over 880}}$

the rejection region is $Z>Z_{\alpha}$

3. Originally Posted by matheagle
test $H_0=.5" alt="H_0=.5" /> vs. $H_a>.5" alt="H_a>.5" />

$\hat p=493/880$ the test statistic is ${\hat p -.5\over \sqrt{(.5)(.5)\over 880}}$

the rejection region is $Z>Z_{\alpha}$
I put $\hat p=493/880$ into the formula:

${(443/880) -.5\over \sqrt{(.5)(.5)\over 880}}=3.573$

is this correct and where do i go from here?

also, where do you use the info about the significance level being = 0.01

4. Originally Posted by mherr
I put $\hat p=493/880$ into the formula:

${(443/880) -.5\over \sqrt{(.5)(.5)\over 880}}=3.573$

is this correct and where do i go from here? Mr F says: Is z = 3.75 significant?

also, where do you use the info about the significance level being = 0.01 Mr F says: Well, if the significance level is 0.01, what's the value of ${\color{red}z_{\alpha}}$? You're expected to be able to look it up ....
Post #2 gives you the solution, all you have to do is fill in the details. How many lessons have you had on this material?

5. z.99 = 2.33