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Math Help - significance level

  1. #1
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    significance level

    880 randomly chosen people surveyed. 493 of them admitted to chewing gum. If we use a signifagant level of 0.01, can we conclude that a majority of people chew gum?
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    MHF Contributor matheagle's Avatar
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    test =.5" alt="H_0=.5" /> vs. >.5" alt="H_a>.5" />

    \hat p=493/880 the test statistic is {\hat p -.5\over \sqrt{(.5)(.5)\over 880}}

    the rejection region is Z>Z_{\alpha}
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  3. #3
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    Quote Originally Posted by matheagle View Post
    test =.5" alt="H_0=.5" /> vs. >.5" alt="H_a>.5" />

    \hat p=493/880 the test statistic is {\hat p -.5\over \sqrt{(.5)(.5)\over 880}}

    the rejection region is Z>Z_{\alpha}
    I put \hat p=493/880 into the formula:

    {(443/880) -.5\over \sqrt{(.5)(.5)\over 880}}=3.573

    is this correct and where do i go from here?

    also, where do you use the info about the significance level being = 0.01
    Last edited by mr fantastic; May 5th 2009 at 05:53 AM. Reason: Merged posts.
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  4. #4
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    Quote Originally Posted by mherr View Post
    I put \hat p=493/880 into the formula:

    {(443/880) -.5\over \sqrt{(.5)(.5)\over 880}}=3.573

    is this correct and where do i go from here? Mr F says: Is z = 3.75 significant?

    also, where do you use the info about the significance level being = 0.01 Mr F says: Well, if the significance level is 0.01, what's the value of {\color{red}z_{\alpha}}? You're expected to be able to look it up ....
    Post #2 gives you the solution, all you have to do is fill in the details. How many lessons have you had on this material?
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  5. #5
    Junior Member plm2e's Avatar
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    z.99 = 2.33
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