Only answer is the book's solution is wrong.
P(red rolls 1,2,3 or sum=11) = P(red rolls 1,2,3)+P(sum=11)-P(red rolls 1,2,3 and sum=11) = 3/6+2/36-0= 20/36 = 5/9
in a dice game, the player independently rolls a fair red die and a fair green die. the player wins if and only if red die shows 1,2 or 3 or if the total on the 2 dice is 11 . Prob(win)=?
In the solution, it says there are 6 ways to get a 1 on the red die, same for 2 or 3...I don't understand. I think it should only have 1 way to get 1 or 2 or 3 because the prob ( #=1) =1/6
Anyone could explain it to me?Thanks!!