Fx(x)= 0 , x<1
Fx(x)= (x^2-2x+2)/2 , 1<= x <2
Fx(x)=1, x>=2
calcualtae the variance of x.
I drew the graph of this function. it is a mixed distribution with a point-mass at 1. But i dont know how to solve it.....
Hello,
Find the pdf f of this function, by differentiating $\displaystyle F_X$
Then the variance is :
$\displaystyle \int_0^2 x^2 f(x) ~dx-\left(\int_0^2 x f(x) ~dx\right)^2$
(definition of the variance)