Originally Posted by

**ayato** Ok, here's the problem i've been having some trouble with:

Ann and Bob have agreed to meet for dinner "around four". The number of minutes after 4:00 that Ann will arrive is approximately normally distributed with mean 10 and standard deviation 3.1, and the number of minutes after 4:00 that Bob will arrive is approximately normally distributed with mean 20 and standard deviation 4.2.

If the longest each will wait is 10 minutes, find the probability that they'll meet?

I know the answer will be around the 1 range but i don't really know how to show the work for it, at least for the work that i showed for it, i'm not confident about it. I'll be very appreciated if someone can help me out. Thank You in advance.