These are binomial probabilities.

The p=1/6 and in the first case n=12 and has a lousy approximation via the central limit theorem since n is small.

The answer to the first one is

.

The second is

where I am assuming that you're including the 14 and 17.

And instead of a normal die you mean a fair die.

You can approximate this via the CLT, the mean is 100/6 and the variance is 100(1/6)(5/6).

The normal superimposed over this binomial is .

Now subtract the mean and divide by the st deviation and use your st normal table.