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Thread: expectation prob

  1. April 11th 2009, 09:04 PM #1
    reflection_009
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    expectation prob

    if E(X)=E(X^2)=1 where E(X) stands expectation of random variable X.
    then find E(X^100)?
    pls help?
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  2. April 11th 2009, 09:15 PM #2
    matheagle
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    The variance is 0, hence P(X=1) =1 .

    So E(X^{anything})=1 .
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