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Math Help - Poisson

  1. #1
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    Poisson

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  2. #2
    MHF Contributor matheagle's Avatar
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    (a)  {e^{-4}4^6\over 6!} .

    (b)  P(X\ge 10) =1-P(X\le 9) where \lambda =8 since this is a two week period and you expect twice as many parts used.

    So,  P(X\ge 10) =1-\sum_{k=0}^9 {e^{-8}8^k\over k!} .

    (c) Here you want three 'successes' in three weeks (binomial) where p is from (a)... \biggl({e^{-4}4^6\over 6!}\biggr)^3 .

    Sorry, I do not understand (d).
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