I’ll try this again, since I didn’t get a solution last time

Please see the attached

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- Apr 1st 2009, 12:56 AMBjornDistribution function problem - (maybe) difficult
I’ll try this again, since I didn’t get a solution last time

Please see the attached - Apr 1st 2009, 09:32 AMLaurent
- Apr 1st 2009, 10:44 PMmatheagle
I get an exponential $\displaystyle \theta$.