Originally Posted by

**matheagle** The first one is correct AND this a hypergeo as long as we are selecting without relacement.

As for the second question, think of it as 3 groups.

(Just brains, no sites.)

You are selecting at least 2 from A, 3 from B, rest from C.

To do that exactly, well thats...

$\displaystyle { {15\choose 2} {7\choose 3} {38\choose 5}\over {60\choose 10}}$

Next figure out all the possibilities, 3 from A, 3 from B, 4 from C....

$\displaystyle { {15\choose 3} {7\choose 3} {38\choose 4}\over {60\choose 10}}$.

FIND all of these and add them together. The complement here is a pain.