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Thread: Hypothesis testing 1 poplulation mean

  1. #1
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    Hypothesis testing 1 poplulation mean

    Hi im new here so
    I am getting trouble with this question, here it is:

    An advertisement for a certain model of mobled phones promised that it allowed '3.5 hours talk time'.A random sample of 8 phones of this type was tested of talk time, x hours, available were as follows:

    3.4,3.7,3.1,3.2,3.6,3.5,3.3,3.4
    {sum of x=27.2, sum of x sqrd = 92.76}

    Carry out a test, at the 5% significance level, to examine whether the advertisement was overstating the length of talk time available from the phone.

    "I got Ps= 3.4 so how do you get Q, i know that Q=1-P, but you will get a -ve!
    Thanks
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  2. #2
    MHF Contributor matheagle's Avatar
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    I'm not sure what you mean by p and q.
    This seems to be a straightforward one sample t-test.

    You want to prove $\displaystyle H_a: \mu< 3.5$ and by default $\displaystyle H_0: \mu= 3.5$.

    Get $\displaystyle \bar X$ and $\displaystyle S^2$.

    Your test stat is $\displaystyle {\bar X-3.5\over S/\sqrt{n}}$

    and your rejection region is $\displaystyle (-\infty, -t_{n-1,\alpha})$.
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  3. #3
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    Ans

    Solution
    I did something
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  4. #4
    MHF Contributor matheagle's Avatar
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    I didn't check your math.
    But one error is your $\displaystyle \mu$'s.
    There's only one mean, so under $\displaystyle H_a$ it's just $\displaystyle \mu$ and not $\displaystyle \mu_1$.
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