i have f(x) = (a+1)x^a 0<x<1

I need to find the cumulative density function.

I have had an attempt but im not confident in my answer. It looks too easy!

$\displaystyle \int_0^x (a+1) t^a \, dt$

$\displaystyle = (a+1) \int t^a \, dt$

$\displaystyle = (a+1) \left[ \frac{t^{a+1}}{(a+1)}\right]_0^x$

$\displaystyle = x^{a+1}$.

Does this look correct at all.

Thanks

sorry but i just could not get latex to work