What you found was , the percentage of scores that are less than 75.
What you're looking for is:
I've already missed two points on this one..but I can't really figure out what I did wrong. Help would be appreciated.
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The scores on a standardized test are normally distributed with a mean of 50 and a standard deviation of 10. What is the percentage of scores that are greater than 75? Use the Standard Normal Table.
my work:
z = (x-mean)/standard dev.
z = (75-50)/10
z = 2.5
then, using the standard normal table... 2.5 give you .9938.
to percentage... 99.38%
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Where did I go wrong? thanks.