Four percent of those who make an airline reservation do not show up for their flight. An airline sells 75 seats for a plane that has 73 seats (overbooking). What is the probability that every person who shows up will get a seat? [The answer is .807]
Let X be the random variable number of people who don't show up.
Originally Posted by garrett88
X ~ Binomial(n = 75, p = 0.04)
Let Y be the random variable number of people who show up.
Y ~ Binomial(n = 75, p = 0.96)