Hello, I have small problem with this problem, here it is

Question :

We pick 3 persons at random from a group of 13 in which exactly 5 have blue eyes.

Let Xi = { 1 if the i ème person has blue eyes

0 if not

What is the joint mass function of X1 and X2?

My actual attempt to a solution

I know that when X1=0 that P(X1=0)=8/13, P(X2=0)=7/12 and P(X2=1)=5/12

and when X1=1 that P(X1=1)=5/13, P(X2=0)=8/12 and P(X2=1)=4/12

I also know that the joint mass function is p(x1, x2) = P(X1 = x1 and X2 = x2)

My question is : so do I write P(X1=0 and X2=0) = P(X1=0) * P(X2=0) = 8/13*7/12

or do I simply write P(X1=0 and X2=0) = (8/13,7/12) or something else???

Thanks a lot.