Thread: probability

assuming iron levels in a solution is evenly distributed with mean of 60g/l and a standard deviation of 6g/l. let x denote the amount of iron in g/l in this solution then x ~ N(60, 6 sqd) calculate the following probabilities

p(x<66)
p(x<68)
p(x>50)
p(50<x<70)
construct a symetric range around mean of x such that 95% of reading taken off this solution will have iron levels in this range

Originally Posted by b2k

assuming iron levels in a solution is evenly distributed with mean of 60g/l and a standard deviation of 6g/l. let x denote the amount of iron in g/l in this solution then x ~ N(60, 6 sqd) calculate the following probabilities

p(x<66)
p(x<68)
p(x>50)
p(50<x<70)
construct a symetric range around mean of x such that 95% of reading taken off this solution will have iron levels in this range

Can you calculate the z-values? Can you use a Strandard Normal Distribution Table? You need to say what yuo're able to do and where you get stuck.

Reading this thread might help: http://www.mathhelpforum.com/math-he...deviation.html