IF A=B with probability 1 then P(A) = P(B)=P(AB)
should this be solved as using addition law as follows ... P (A ∪ B) = P (A) + P (B) = 1 i am not sure ... does anyone have any input?
Follow Math Help Forum on Facebook and Google+
This is how I see it:
P(AB)=P(A¬B).P(B) but P(A¬B)=1 as A=B with probability one
Analogously, P(AB)=P(B¬A)P(A) => P(AB)=P(A)
"¬" denotes conditional probability(sorry don't know how to use latex)
View Tag Cloud