IF A=B with probability 1 then P(A) = P(B)=P(AB) should this be solved as using addition law as follows ... P (A ∪ B) = P (A) + P (B) = 1 i am not sure ... does anyone have any input?
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This is how I see it: P(AB)=P(A¬B).P(B) but P(A¬B)=1 as A=B with probability one => P(AB)=P(B) Analogously, P(AB)=P(B¬A)P(A) => P(AB)=P(A) "¬" denotes conditional probability(sorry don't know how to use latex)
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