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Math Help - Geometric Distribution/Confidence Intervals

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    Geometric Distribution/Confidence Intervals

    A die is thrown repeatedly and independently until the score of 6 is obtained. This happens to be on the 8th throw. Find an equi-tailed 95% confidence interval for theta=P(six)?

    I understand that the die process follows a geometric distribution. But I can only understand confidence intervals when using a normal distribution? I can calculate the E(X) and Var (X) for the distribution, but i don't see how to calculate the confidence interval? As far as I'm aware the geometric distribution has no fixed "n" and therefore can't calculate the interval in the same way.

    Regards
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    Quote Originally Posted by myeyesfeelmessedup View Post
    A die is thrown repeatedly and independently until the score of 6 is obtained. This happens to be on the 8th throw. Find an equi-tailed 95% confidence interval for theta=P(six)?

    I understand that the die process follows a geometric distribution. But I can only understand confidence intervals when using a normal distribution? I can calculate the E(X) and Var (X) for the distribution, but i don't see how to calculate the confidence interval? As far as I'm aware the geometric distribution has no fixed "n" and therefore can't calculate the interval in the same way.

    Regards
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