[SOLVED] Probability

**ninano1205** · February 1st 2009, 11:26 AM

Is it asking P(X>=3/4) / P(X>=1/2)?

**mr fantastic** · February 1st 2009, 06:05 PM

Originally Posted by ninano1205

Is it asking P(X>=3/4) / P(X>=1/2)?

Yes.

$\Pr\left(X \geq \frac{3}{4} \left| X \geq \frac{1}{2} \right. \right) = \frac{\Pr\left(X \geq \frac{3}{4}\right)}{ \left(X \geq \frac{1}{2}\right)}$ .

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