I am having difficulty solving this problem...
What is the probability of getting more 6's than 5's on four
tosses of a fair six-sided die?
I'm not sure how to set up the different cases...
P(6-6-6-5), P(6-6-5-x) and ???? How do I factor in other case such
as rolling one 6 and no 5's? The answer is 0.325 but I don't know how
to arrive at this answer. Thanks, Nancy