I am having difficulty solving this problem...

What is the probability of getting more 6's than 5's on four

tosses of a fair six-sided die?

I'm not sure how to set up the different cases...

P(6-6-6-5), P(6-6-5-x) and ???? How do I factor in other case such

as rolling one 6 and no 5's? The answer is 0.325 but I don't know how

to arrive at this answer. Thanks, Nancy