The word APE can only be arranged in 6 ways, so that kind of boils it down.
The word APE are written on the three cards, with one letter on each card. The three card are then shuffled and dealt face up in a line to form " word". Q1. List the possible equally likely "words" that could be so formed
Q2. List the probability that the "word" so formed:
(a) is the APE
(b) is not the word PEA
(c) starts with an A
(d) does not start with E
(e) has A and E as immediate neighbours in any order
thank u for your time
Q1. List the possible equally likely "words" that could be so formed
ans: 3! = 6 i.e APE , AEP, PAE, PEA, EAP, EPA
Q2. List the probability that the "word" so formed:
(a) is the APE
P (APE) = 1/6
(b) is not the word PEA
P( not PEA) = 5/6
(c) starts with an A
P( start with A) = 2/6 = 1/3
(d) does not start with E
P( not start with E) = 4/6 = 2/3
(e) has A and E as immediate neighbours in any order
???--stuck--what it mean by 'immediate neighbours in any order'
so hope some one can reconfirm my answers on Q2 (a) to (d) and help me on guestion (e)
Tq again
mattty & galactus...
i am veery sorry .. it my mistake on what i'm writing here on 2e ans..
for 2(c) the ans is 2/3 (our ans 1/3)
2(e) the ans is 1/3 (our ans 1/3)
i'm verry sorry on that...
so we have the correct ans for 2(e) but not for 2(c).. but i think our ans on 2(c) is correct i.e 2/3...
sorry for inconvenience