Find the probability that in a group of 3 people no two have the same birthday assuming that a year has 365 days .
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Originally Posted by mathaddict Find the probability that in a group of 3 people no two have the same birthday assuming that a year has 365 days . Can you find the probability that 2 people from 3 DO have the same birthday?
probability that all will have different Birthdays =(365X364X363) /( 365X365X365) =(364X363) / (365X365)
Originally Posted by mathaddict Find the probability that in a group of 3 people no two have the same birthday assuming that a year has 365 days . Same technique as post #6 in this thread: http://www.mathhelpforum.com/math-he...-problems.html Google birthday paradox for a lot more info.
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