Find the probability that in a group of 3 people no two have the same birthday assuming that a year has 365 days .

Printable View

- Jan 19th 2009, 05:42 AMmathaddictBIrthday probability
Find the probability that in a group of 3 people no two have the same birthday assuming that a year has 365 days .

- Jan 19th 2009, 06:39 AMMush
- Jan 19th 2009, 06:49 AMsumit2009
**probability that all will have different Birthdays**)

=(365X364X363**/( 365X365X365)**

=(364X363) / (365X365) - Jan 19th 2009, 09:15 AMmr fantastic
Same technique as post #6 in this thread: http://www.mathhelpforum.com/math-he...-problems.html

Google**birthday paradox**for a lot more info.