Hi can some help me with this question as i don't understand it at all, and just do not know were to begin. (Headbang)

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- Jan 17th 2009, 11:52 AMnerdoHard Statisitics question
Hi can some help me with this question as i don't understand it at all, and just do not know were to begin. (Headbang)

- Jan 17th 2009, 03:09 PMLast_Singularity
I can get you started.

Part A:

There are a lot choices. Simply pick a measurement in units of customary and metric. Example: pounds vs. kilograms, miles vs. kilometers, Fahrenheit vs. Celsius, etc.

For instance, take a temperature conversion. We know that the relationship between F and C is: $\displaystyle F = 9/5 C + 32$.

So if $\displaystyle y_i$ represented Fahrenheit and $\displaystyle x_i$ represented Celsius, then $\displaystyle a$ is $\displaystyle 9/5$ and $\displaystyle b$ is 32.

Part B:

(i)

$\displaystyle \bar{y} = \frac{1}{n} \sum_{i=1}^{n} y_i = \frac{1}{n} \sum_{i=1}^{n} (a x_i + b) = \frac{a}{n} \sum_{i=1}^{n} x_i + \frac{1}{n} \sum_{i=1}^{n} b = a \bar{x_i} + b$

So the claim is true, as proven by algebra above.

(ii)

For $\displaystyle \bar{z}$, the claim is false. It is up to you to find a counterexample. Pick any arbitrary set of values for $\displaystyle x_i$ and see whether or not $\displaystyle \bar{z} = \frac{1}{n} \sum_{i=1}^{n} \frac{c}{x_i}$ is equal to $\displaystyle \frac{c}{\bar{x}}$. Most likely not, if you picked your values strategically.

(iii)

Since the relationship between $\displaystyle y_i,x_i$ is linear (and thus bijective), the ordering of the values of $\displaystyle x_i$ are preserved during a mapping to $\displaystyle y_i$. Thus, the smallest value of $\displaystyle x_i$ gets sent to the smallest value of $\displaystyle y_i$. Same with the largest value and the median, etc.

(iv)

Again, find a counterexample.