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Math Help - ˚F to ˚C. New estimated regression line?

  1. #1
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    Exclamation ˚F to ˚C. New estimated regression line?

    GIVEN:
    x=˚F, y= deflection adjustment factor (y≥0)
    n=15 ∑x(sub i)=1425 ∑y(sub i)=10.68
    ∑x(sub i)=139,037.25 ∑x(sub i)y(sub i)=987.645
    ∑y(sub i)=7.8518

    QUESTION
    c. Suppose temperature were measured in ˚C rather than in ˚F. What would be the estimated regression line?

    MY WORKING SOLUTION
    I calculated the est. regression line for ˚F and got:
    y= 1.377-.00376x.

    Do I only do this to get the new regression line:
    y=[5/9(1.377-32)] - [5/9(.00376-32)]x?

    Thanks,
    Yvonne
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  2. #2
    Grand Panjandrum
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    Quote Originally Posted by yvonnehr View Post
    GIVEN:
    x=˚F, y= deflection adjustment factor (y≥0)
    n=15 ∑x(sub i)=1425 ∑y(sub i)=10.68
    ∑x(sub i)=139,037.25 ∑x(sub i)y(sub i)=987.645
    ∑y(sub i)=7.8518

    QUESTION
    c. Suppose temperature were measured in ˚C rather than in ˚F. What would be the estimated regression line?

    MY WORKING SOLUTION
    I calculated the est. regression line for ˚F and got:
    y= 1.377-.00376x.

    Do I only do this to get the new regression line:
    y=[5/9(1.377-32)] - [5/9(.00376-32)]x?

    Thanks,
    Yvonne
    No, you have:

     <br />
y= 1.377-.00376x_f<br />

    where x_f is the tempratue in Fahrenheit. Now x_f=(9/5)x_c+32 where x_c is the corresponding temprature in Centigrade so:

     <br />
y= 1.377-.00376((9/5)x_c+32)<br />

    CB
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