Can someone help me with the following question:

In the 1989 US Open Golf Championship, 4 golfers made hole-in-one on the 6th hole.The probability of a professional golfer making a hole in one (on any given hole) is estimated to be 1/3709.

There were 155 golfers participating in the second round. Assuming the estimate given above, what is the probability that exactly 4 of the 155 golfers would get a hole-in-one on the sixth hole?