Question:

Suppose (Omega) = {a,b,c}, P({a,b}) = 0.7 , and P({b,c}) = 0.6 Compute the probabilities of {a}, {b}, {c}

Kind of lost with the question.

Printable View

- October 8th 2006, 03:59 PMmathlgCompute the probabilities
Question:

Suppose (Omega) = {a,b,c}, P({a,b}) = 0.7 , and P({b,c}) = 0.6 Compute the probabilities of {a}, {b}, {c}

Kind of lost with the question. - October 8th 2006, 09:42 PMCaptainBlack
Let A=P({a}), B=P({b}), C=P({c}), then

A + B + C = 1

A + B = 0.7

B + C = 0.6.

Which is a set of three simultaneous linear equations in three unknowns,

which can be solved by the usual methods.

Eq(2) + Eq(3) - Eq(1) gives:

(A + B) + (B + C) - (A + B + C) = 0.7 + 0.6 - 1

or:

B = 0.3.

The substituting this in to Eq2 gives A=0.4, and into Eq3 gives C=0.3.

RonL