Probabilities:

Number of Customers in the System ---- Probability

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0 ---- 0.5600

1 ---- 0.2464

2 ---- 0.1084

3 ---- 0.0477

4 ---- 0.0210

5 ---- 0.0092

6 OR MORE ---- 0.0073

The probability that a customer will have to wait is 0.4400. Thus the probability that that will not is 0.5600.

(1) What is the probability that 1 customer is receiving a haircut and no one is waiting?

I figured it like this: P(not waiting) = 0.5600

P(1 customer in the system) = 0.2464

P(not waiting ∩ 1 customer in the system) = 0.5600 * 0.2464 = 0.137984 <--- Does that seem right?

(2) The probability of 2 customers being in the system is .1084. The probability that they will have to wait is .4400, and therefore the probability that they will NOT have to wait is .5600. What is the probability that 2 customers are in the system, and 1 is waiting and 1 is NOT waiting?

(3) The probability of 3 customers being in the system is .0477. The probability that they will have to wait is .4400, and therefore the probability that they will NOT have to wait is .5600. What is the probability that 3 customers are in the system, and 2 are waiting and 1 is NOT waiting?

THANK YOU!