I'm trying to do the following problem and I'm having trouble figuring out how to set up my integrals:
Suppose that and are uniformly distributed over the triangle defined by the following points on y1,y2:
(-1,0), (0,1), (1,0)
What I've been able to do up to the point I'm confused:
Because it's uniformly distributed over a triangle, I found that the probability is uniformly distributed over area: bh/2 = 2*1/2 = 1
Therefore, I get the distribution function:
Now I can't figure out how to write the double-integral, can I just use one or do I have to find the sum of different components of the part of the triangle that fits the constraints?