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Thread: random var X's probability distribution

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    random var X's probability distribution


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    Rhymes with Orange Chris L T521's Avatar
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    Quote Originally Posted by ndcruz View Post
    Find $\displaystyle \mu=E(X)$, $\displaystyle \sigma^2$ and then $\displaystyle \sigma$

    Recall that:

    $\displaystyle \mu=E(X)=\sum_{x} xP(x)$

    $\displaystyle \sigma^2=E(X^2)-\left[E(X)\right]^2=\left[\sum_x xP(x) \right]-\mu^2$

    $\displaystyle \sigma=\sqrt{E(X^2)-\left[E(X)\right]^2}=\sqrt{\left[\sum_x xP(x) \right]-\mu^2}$

    Do you think that you can solve the problem now?

    --Chris
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