A company takes on an average of 0.1 new employees per week. Assume that the actual
number of employees taken on in a given week has a Poisson distribution.
no idea how to answer these (ii) Let Y denote the number of weeks that pass without a new employee being taken on.
Calculate the expectation of Y .
(iii) Calculate the probability that, over the course of a year (50 working weeks), there is
just one week when more than one new employee is taken on.
the answers are 10.51 weeks and 0.1859 or 0.1852 using the binomial approx many regards !!!!