Let random variable X have the cdf F given by:
F(x)= { 0 for x ≤ 0
(x^3/8) for 0< x<2
1 for x ≥ 2
1. Find P(X ≤ 2/3)
[(2/3)^3]/8 = .37
2. Find the probability density function for X
f(x) = x^2/16
3. Let random Variable Y = F(X). Find the Probability P(Y ≤ 2/3)
I just want to check my answers for parts 1 and 2. Can someone please help me with part 3