Given that fx(x) = 0 (x <= 10)

= 10/x^2 (x >10)

Find the 60-th percentile of X.

How do we solve this?

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- Nov 2nd 2008, 08:15 AMdingdongHow to find certain percentile of X
Given that fx(x) = 0 (x <= 10)

= 10/x^2 (x >10)

Find the 60-th percentile of X.

How do we solve this? - Nov 2nd 2008, 03:18 PMCaptainBlack