Pr(IA = 1) = Pr(A), Pr(IA = 0) = Pr(A') = 1 - Pr(A).

Pr(IB = 1) = Pr(B), Pr(IB = 0) = Pr(B') = 1 - Pr(B).

(a) Let X = (IA + IB)^2. Then the possible values of X are X = 0, 1, 4.

What combination of IA and IB gives X = 0? Therefore Pr(X = 0) = .....

What combinations of IA and IB give X = 1? Therefore Pr(X = 1) = .....

What combination of IA and IB gives X = 4? Therefore Pr(X = 4) = .....

(b) E(X) = 0 Pr(X = 0) + 1 Pr(X = 1) + 4 Pr(X = 4) = ....