Results 1 to 3 of 3

Math Help - expected value: this easy?

  1. #1
    Junior Member
    Joined
    Aug 2007
    Posts
    71

    expected value: this easy?

    Isn't the solution just 1+2+3+4+5+6 = 21?
    Attached Thumbnails Attached Thumbnails expected value: this easy?-problem.jpg  
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Member
    Joined
    Oct 2008
    Posts
    156
    What is your reasoning? First of all, what is your random variable  X ? Define that first. Then look at  E(X) . There are  6 outcomes. What is the probability of each outcome? You can also think about this as rolling a six-sided die.
    Last edited by manjohn12; October 22nd 2008 at 11:27 PM.
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Member
    Joined
    Oct 2008
    Posts
    156
    It would be  6(1+\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+\frac{1}{5  }+\frac{1}{6}) .
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Replies: 2
    Last Post: February 9th 2013, 09:59 PM
  2. Easy Easy Trig help
    Posted in the Trigonometry Forum
    Replies: 3
    Last Post: November 28th 2009, 12:09 AM
  3. Seemingly easy question... too easy.
    Posted in the Pre-Calculus Forum
    Replies: 3
    Last Post: August 23rd 2009, 10:36 PM
  4. easy, easy question
    Posted in the Discrete Math Forum
    Replies: 3
    Last Post: July 14th 2009, 08:38 AM
  5. Easy probability that is not so easy for me!
    Posted in the Statistics Forum
    Replies: 1
    Last Post: May 9th 2009, 08:03 AM

Search Tags


/mathhelpforum @mathhelpforum