the first card drawn cannot be card a or e. second card cannot be card a or e also. then probability of the third card drawn is card a or e.
Six cards labelled A, B, C, D, E and F are drawn one at a time from a hat. What is the probability that card A or card E will be the third card drawn?
How do I even start this?
= (a or e is not chosen)(a or e is not chosen for the second time)(a or e is chosen)
= (4/6)(3/5)(2/4)
= 1/5
A or E can be drawn on the first or second time, but they cannot both be drawn before the first time. So you have the add the probability that A is drawn on the first time or second time and E on the third time and also that E is drawn before the third time and A on the third time.