Looks Binomial to me.

when X is Bi(n=no of trials,p=probabilty of success)

Use P(X=x) = nCx p^x(1-p)^n-x

with:

p (prob of reservation being made) = .30

n = 10

a. P(X=10) = 10C10(.3)^10(1-.3)^10-10

b. each call was independant of the next.

c. P(X>=1) = P(X=1)+P(X=2)+P(X=3)+....+P(X=10)

= 1-P(X=0)

= 10C0(.3)^0(1-.3)^10-0