Looks Binomial to me.
when X is Bi(n=no of trials,p=probabilty of success)
Use P(X=x) = nCx p^x(1-p)^n-x
p (prob of reservation being made) = .30
n = 10
a. P(X=10) = 10C10(.3)^10(1-.3)^10-10
b. each call was independant of the next.
c. P(X>=1) = P(X=1)+P(X=2)+P(X=3)+....+P(X=10)